|

楼主 |
发表于 12-12-2010 05:04 PM
|
显示全部楼层
可怜0回复 |
|
|
|
|
|
|
|
发表于 12-12-2010 05:23 PM
|
显示全部楼层
HCOOH is weak acid,HCOOK is salt of HCOO-
the solution is buffer..
if want to find pH,jz substitute formula
pH= -log Ka-log(conc of acid/conc of salt)
= -log 1.74^-4 - log ( 0.3/0.52)
=4.008
= 4.1 |
|
|
|
|
|
|
|

楼主 |
发表于 12-12-2010 08:05 PM
|
显示全部楼层
回复 3# sookchin
娃哈哈!谢谢你~知道我哪里错了~粗心啊!con. base 和con.acid倒转了 |
|
|
|
|
|
|
| |
本周最热论坛帖子
|