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发表于 19-5-2006 12:23 PM
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further math 1)
Let x^3 - px^2 + qx - r = 0 has the root a,b,c . Then
p = a+b+c=0
q = ab+bc+ca = 1/2 [ (a+b+c)^2 - (a^2+b^2+c^2)] = -8
Denote Sk as the sum of degree k , then by Newton Sum ,
S3 - pS2 + qS1 - 3r = 0 ==> -9 - 3r = 0 --> r = -3
==> x^3 - 8x - 3 = 0
==> x^4 - 8x^2 - 3x = 0
Again by Newton Sum S4 - 8S2 - 3S1 = 0 --> S4 = 8(16) = 128
**Note : Sk = a^k + b^k + c^k |
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