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发表于 15-12-2010 09:41 PM
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本帖最后由 junchung2003 于 15-12-2010 09:43 PM 编辑
回复 101# whyyie
解congruent吗?
你的方法也是可以的。
我分享我的方法。
<ABL = <BCP (From a)
<BAL = <KBC = 90 (Angle of square)
<ALB = <BKC (Sum of interior of a ∆ )
AB = BC (Side of a square)
Hence ∆ABL congruent to ∆BCK (SAA)
至于part c
<KPC = < BPC (Given)
<ABL = <BCP (From a)
<BKP = < PBC (Sum of interior of a ∆ )
Hence, ∆KPB similar to ∆BPC |
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