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发表于 1-9-2007 11:03 PM
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发表于 2-9-2007 10:34 AM
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原帖由 nikuang04 于 1-9-2007 11:03 PM 发表
问一题 ionic equilibria的问题,(个人觉得 ionic equilibria是最难的了)
In an experiment to determine the dissociation constant, Ka of ethanoic acid, it was found that only 0.018& of 0.20 mol dm-3 ethanoic acid dissociated in a solution of pH=1.0. What is the Ka value in mol dm-3?
这是gram吗???
是要找equilibrium是多少,然后再用 alfa︿2=KaC???
原帖由 nikuang04 于 1-9-2007 11:03 PM 发表
好难
a)不是很懂
是不是要 preserve the quality (看题目的)
b) ethane-1,2-diol is more polar, stronger attrative force
higher boiling points, non-volatile
more hy ...
(a) Water causes wood to rot and decay whereas ethane-1,2-diol does not causes wood to rot.
(b)Ethane-1,2-diol does not burn easily whereas ethanol and hexane are easily burned .
(c)Ethane-1,2-diol is less volatile than water,ethanol,and hexane.
最后一个对了
[ 本帖最后由 jiko 于 2-9-2007 10:36 AM 编辑 ] |
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发表于 2-9-2007 11:38 AM
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原帖由 jiko 于 2-9-2007 10:34 发表
这是gram吗???
是要找equilibrium是多少,然后再用 alfa︿2=KaC???
(a) Water causes wood to rot and decay whereas ethane-1,2-diol does not causes wood to rot.
(b ...
是 %
要找Ka of ethanoic acid |
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发表于 2-9-2007 11:42 AM
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回复 #561 nikuang04 的帖子
請問Ka = 0.0537mol per dm^3嗎? |
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发表于 2-9-2007 11:47 AM
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原帖由 Leong13 于 2-9-2007 11:42 发表
請問Ka = 0.0537mol per dm^3嗎?
不是啦
没有这样大 |
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发表于 2-9-2007 11:57 AM
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发表于 2-9-2007 12:03 PM
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原帖由 Leong13 于 2-9-2007 11:57 发表
6.48^-9 mol dm^-3
也不对
没有这样小 |
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发表于 2-9-2007 12:05 PM
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发表于 2-9-2007 03:13 PM
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jiko,你乱乱来的答案也能对?
解答是这样的:
CH3COOH -->< CH3COO- + H+
[CH3COOH] = 0.20-0.018/100 X 0.20 ==(approximately) 0.20
[CH3COO-] = 0.018/100X0.20 = 3.6X10^-5 mol dm-3
[H+] = 10^ -1 (from solution of pH1.0) +  0.018/100X0.20 ( from dissociation of acid) approximately = 0.10 mol dm-3
therefore, Ka = 0.10 X 3.6X10^-5 / 0.20
= 1.8 X 10^-5 mol dm-3 |
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发表于 2-9-2007 10:25 PM
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发表于 2-9-2007 11:58 PM
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再来一题 acid and base
Explain why the acid strength increases in the following order:
HClO<HClO2<HClO3<HClO4 |
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发表于 3-9-2007 01:56 PM
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原帖由 nikuang04 于 2-9-2007 11:58 PM 发表
再来一题 acid and base
Explain why the acid strength increases in the following order:
HClO
inorganic来的???? |
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发表于 3-9-2007 01:59 PM
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原帖由 jiko 于 3-9-2007 13:56 发表
inorganic来的????
我在acid base 读到的喔
那本TYT的 |
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发表于 3-9-2007 07:13 PM
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回复 #574 nikuang04 的帖子
是因為O比較electronegative,pull the electron from Cl and weaken the HCl bond , hydrogen ion can release more easily.
so more the o in a compound the hydrogen is more easy to dissociate and give acid characteristic嗎? |
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发表于 3-9-2007 07:56 PM
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原帖由 Leong13 于 3-9-2007 19:13 发表
是因為O比較electronegative,pull the electron from Cl and weaken the HCl bond , hydrogen ion can release more easily.
so more the o in a compound the hydrogen is more easy to dissociate and giv ...
就是这样啦
各位也来出题啊 |
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发表于 3-9-2007 09:04 PM
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我覺的是一題很好的問題,大家試試吧!
what is the volume ratio of 0.20 mol dm^-3 CH3COOH and 0.15mol dm^-3 CH3COONa that must be mixed to prepare a solution with pH 5.22 ( Ka CH3COOH = 1.8 x 10^-5 ) |
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发表于 4-9-2007 12:32 AM
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原帖由 Leong13 于 3-9-2007 21:04 发表
我覺的是一題很好的問題,大家試試吧!
what is the volume ratio of 0.20 mol dm^-3 CH3COOH and 0.15mol dm^-3 CH3COONa that must be mixed to prepare a solution with pH 5.22 ( Ka CH3COOH = 1.8 x 10^-5 )
这个是一个 buffer solution
因为有 weak acid ( ethanoic acid) 和 weak acid 的 salt (CH3COONa)
所以呢, CH3COOH --->< CH3COO- + H+
Ka=[CH3COO-][H+]/[CH3COOH]
[H+] = Ka X [CH3COOH] / [CH3COO-]
pH = pKa + 1g[CH3COO-]/[CH3COOH]
5.22= -lg1.8X10^-5 + 1g[CH3COO-]/[CH3COOH]
[CH3COO-]/[CH3COOH] = 2.99
0.15 X Vsalt
--------------  = 2.99
0.20 X Vacid
得 Vsalt/Vacid=3.99
也就是说可以 mix 3.99dm3 of CH3COONa with 1 dm3 of ethanoic acid
不懂对吗?
[ 本帖最后由 nikuang04 于 4-9-2007 03:07 PM 编辑 ] |
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发表于 4-9-2007 02:36 PM
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回复 #578 nikuang04 的帖子
上面那部分對,可是你好像把acid和salt的mol弄錯了。 |
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发表于 4-9-2007 03:08 PM
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原帖由 Leong13 于 4-9-2007 14:36 发表
上面那部分對,可是你好像把acid和salt的mol弄錯了。
不好意思啊,把0.15和0.20到反了
这样对了吗? |
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发表于 4-9-2007 04:49 PM
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