佳礼资讯网

 找回密码
 注册

ADVERTISEMENT

查看: 1428|回复: 1

帮我解答PHYSICS

[复制链接]
发表于 12-11-2006 05:18 PM | 显示全部楼层 |阅读模式
希望有人可以帮我解答。。。 满容易的。。。

A wheel of radius r = 1 m rotates with an angular velocity w = 2.2 rad/s counter-clockwise, and an angular acceleration a = 1.6 rad/s clockwise. Determine the magnitude and direction of P at this instant.

P is located exactly above the wheel with tangent line slope m = 0. Direction y = vertical and x = horizontal.
回复

使用道具 举报


ADVERTISEMENT

发表于 23-11-2006 06:12 PM | 显示全部楼层
Assume the wheel is rolling without slipping. At any instant of time, the point on the wheel in contact with the ground is the instantaneous center of zero velocity. Thus the velocity of P is simply v = w(2r) = 2.2(2)=4.4m/s to the left.
回复

使用道具 举报

您需要登录后才可以回帖 登录 | 注册

本版积分规则

 

ADVERTISEMENT



ADVERTISEMENT



ADVERTISEMENT

ADVERTISEMENT


版权所有 © 1996-2023 Cari Internet Sdn Bhd (483575-W)|IPSERVERONE 提供云主机|广告刊登|关于我们|私隐权|免控|投诉|联络|脸书|佳礼资讯网

GMT+8, 30-11-2024 07:42 PM , Processed in 0.096296 second(s), 21 queries , Gzip On.

Powered by Discuz! X3.4

Copyright © 2001-2021, Tencent Cloud.

快速回复 返回顶部 返回列表